- Is it necessary to have oh group of phenol valways at ortho . . . - Socratic
No, the "OH" group in phenol is by definition at "C1" > The structure of phenol is You can draw the structure like this: phenol2 However, the structure is not meta-phenol It is phenol because the ring carbon attached to the "OH" group is now "C1" The "OH" carbon can be on any carbon atom of the ring, and the compound is still phenol,
- What is the product of the following reaction? 1)CH_3 OH - Socratic
These are ostensibly acid-base reactions For ammonium we could write NH_4^+ +HO^(-) rarr NH_3(aq) + H_2O(l) For methanol, the acid base reaction would proceed
- Question #74006 - Socratic
(d) is the correct option CH_3CH(OH)CH_2CH_2CH_3 (pentan-2-ol) being secondary alcohol on oxidation first tansformed into ketone CH_3CH(OH)CH_2CH_2CH_3stackrel([O])-> CH_3COCH_2CH_2CH_3 Further oxidation of ketone is difficult but can be performed in extreme conditions and oxidation product is obtained following Popoff's rule Popoff's rule states that during oxidation of unsymmetrical
- Site Map - Naming Carbohydrate Questions and Videos | Socratic
Questions and Videos on Naming Carbohydrate, within Organic Chemistry
- Can you give the IUPAC name for the following (CH_3)_3C-OH . . . - Socratic
So this is a propanol derivative: "2-methylpropan-2-ol" For "isopropyl alcohol", H_3C-CH (OH)CH_3, the longest chain is again three carbons long, and C2 is substituted by -OH, so "propan-2-ol" I think this is right, and I haven't broken any arcane rule Both names seem to be unambiguous
- Question #54b11 - Socratic
The balanced equation is "CH"_3"CH"_2"COO"^"-" + "3S" + 4"OH"^"-" → "CH"_3"COO"^"-" + "HCO"_3^"-" + "3HS"^"-" + "H"_2"O" > The reaction is carried out at pH 8, so we must balance in basic solution
- Question #851e9 + Example - Socratic
The equation for this is: H^+ (aq)+OH^ (-) (aq)rightleftharpoonsH_2O (l) A common example of a neutralization reaction would be adding hydrochloric acid to aqueous sodium hydroxide
- Question #5392e - Socratic
Here's what I get Step 1 Write the molecular equation "Fe" ("NO"_3)_3" (aq)"+ "3NH"_3" (aq)" + "3H"_2"O (l)" → "Fe (OH)"_3" (s)" + "3NH"_4"NO"_3" (aq)" Step 2
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