- On the hydrolysis of esters according to the reaction: HCOO . . . - Socratic
HCOO^(-)(aq) + H_2O(l) rightleftharpoons HCOOH(aq) + OH^(-)(aq) If the solution is diluted, the reaction will shift left, because (i) water isn't in the equilibrium expression, and (ii) each product is in aqueous solution If NaOH is added, then we have increased the concentration of hydroxide ions The reaction will shift left to re-equilibrate and consume the excess OH^- Pressure will have
- Is it necessary to have oh group of phenol valways at ortho . . . - Socratic
No, the "OH" group in phenol is by definition at "C1" > The structure of phenol is You can draw the structure like this: phenol2 However, the structure is not meta-phenol It is phenol because the ring carbon attached to the "OH" group is now "C1" The "OH" carbon can be on any carbon atom of the ring, and the compound is still phenol,
- 6-10. What are the name of the following compounds? a. Ca (OH)2 b. Fe . . .
Generally, OH adds "hydroxide" to an inorganic compound's name Moreover, element names aren't capitalized unless at the beginning of a sentence We write iron (II) hydroxide instead of just iron hydroxide as iron takes the form of its +2 oxidation state, out of its 10 oxidation states
- Question #50782 - Socratic
sf(pH=7 04) This is a very dilute solution of NaOH so I would expect the pH to be 7 or very slightly above Because the concentration is so low we must also take into account the ions that are formed from the dissociation of water: sf(H_2OrightleftharpoonsH^++OH^-) sf(K_w=[H^+][OH^-]=10^(-14) at sf(25^@C) If you do a thought experiment you can imagine adding a small amount of NaOH to water
- Can you give the IUPAC name for the following (CH_3)_3C-OH . . . - Socratic
So this is a propanol derivative: "2-methylpropan-2-ol" For "isopropyl alcohol", H_3C-CH (OH)CH_3, the longest chain is again three carbons long, and C2 is substituted by -OH, so "propan-2-ol" I think this is right, and I haven't broken any arcane rule Both names seem to be unambiguous
- Question #a9dd1 + Example - Socratic
There are many, but the two you're likely being asked for are: Hydroxide (OH^-) Ammonium (NH_4^+) There are many polyatomic ions that don't end in "-ite" or "-ate" For example: Hydroxide (OH^-) Ammonium (NH_4^+) Cyanide (CN^-) Peroxide (O_2^(2-)) The first 2 are likely the ones that you're being asked for -- they're extremely common across general chemistry, and it will do you credit to have
- Question #97503 - Socratic
Here's what I get The general equation for the dissociation of a carboxylic acid is "R-COOH + H"_2"O" ⇌ "R-COO"^"-" + "H"_3"O"^+ All we have to do is write the
- Question #0a25a - Socratic
Lithium hydroxide has a mass of 24 g per mole, so 2 50 g is 0 104 mole Dissolve this in 1 50 L, and the concentration is [LiOH] = 0 104 mol -: 1 50 L = 0 0694 "mol" L Since LiOH is a strong base, it ionizes completely LiOH rarr Li^+ + OH^- Since each one mole of LiOH produces one mole of OH^-, the concentration of OH^- will be 0 0694 mol L as well
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