- On the hydrolysis of esters according to the reaction: HCOO . . . - Socratic
HCOO^(-)(aq) + H_2O(l) rightleftharpoons HCOOH(aq) + OH^(-)(aq) If the solution is diluted, the reaction will shift left, because (i) water isn't in the equilibrium expression, and (ii) each product is in aqueous solution If NaOH is added, then we have increased the concentration of hydroxide ions The reaction will shift left to re-equilibrate and consume the excess OH^- Pressure will have
- Is it necessary to have oh group of phenol valways at ortho . . . - Socratic
No, the "OH" group in phenol is by definition at "C1" > The structure of phenol is You can draw the structure like this: phenol2 However, the structure is not meta-phenol It is phenol because the ring carbon attached to the "OH" group is now "C1" The "OH" carbon can be on any carbon atom of the ring, and the compound is still phenol,
- 6-10. What are the name of the following compounds? a. Ca (OH)2 b. Fe . . .
Generally, OH adds "hydroxide" to an inorganic compound's name Moreover, element names aren't capitalized unless at the beginning of a sentence We write iron (II) hydroxide instead of just iron hydroxide as iron takes the form of its +2 oxidation state, out of its 10 oxidation states
- Can you give the IUPAC name for the following (CH_3)_3C-OH . . . - Socratic
So this is a propanol derivative: "2-methylpropan-2-ol" For "isopropyl alcohol", H_3C-CH (OH)CH_3, the longest chain is again three carbons long, and C2 is substituted by -OH, so "propan-2-ol" I think this is right, and I haven't broken any arcane rule Both names seem to be unambiguous
- Question #97503 - Socratic
Here's what I get The general equation for the dissociation of a carboxylic acid is "R-COOH + H"_2"O" ⇌ "R-COO"^"-" + "H"_3"O"^+ All we have to do is write the
- Question #0a25a - Socratic
Lithium hydroxide has a mass of 24 g per mole, so 2 50 g is 0 104 mole Dissolve this in 1 50 L, and the concentration is [LiOH] = 0 104 mol -: 1 50 L = 0 0694 "mol" L Since LiOH is a strong base, it ionizes completely LiOH rarr Li^+ + OH^- Since each one mole of LiOH produces one mole of OH^-, the concentration of OH^- will be 0 0694 mol L as well
- Question #7c802 + Example - Socratic
Oxides that form neither an acid nor a base, in combination with water Acid oxides will react with water to ultimately give off H^+: Sulphur trioxide SO_3 will form sulfuric acid: SO_3 (g) + H_2O (l)->H_2SO_4 which will give off H^+ Basic oxides will accept H^+: Calcium oxide CaO will form a base: CaO (s)+H_2O (l)->Ca (OH)_2 The OH^- part combining with H^+ to form water Ferrous oxide FeO
- Question #74006 - Socratic
(d) is the correct option CH_3CH(OH)CH_2CH_2CH_3 (pentan-2-ol) being secondary alcohol on oxidation first tansformed into ketone CH_3CH(OH)CH_2CH_2CH_3stackrel([O])-> CH_3COCH_2CH_2CH_3 Further oxidation of ketone is difficult but can be performed in extreme conditions and oxidation product is obtained following Popoff's rule Popoff's rule states that during oxidation of unsymmetrical
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