- On the hydrolysis of esters according to the reaction: HCOO . . . - Socratic
HCOO^(-)(aq) + H_2O(l) rightleftharpoons HCOOH(aq) + OH^(-)(aq) If the solution is diluted, the reaction will shift left, because (i) water isn't in the equilibrium expression, and (ii) each product is in aqueous solution If NaOH is added, then we have increased the concentration of hydroxide ions The reaction will shift left to re-equilibrate and consume the excess OH^- Pressure will have
- Is it necessary to have oh group of phenol valways at ortho . . . - Socratic
No, the "OH" group in phenol is by definition at "C1" > The structure of phenol is You can draw the structure like this: phenol2 However, the structure is not meta-phenol It is phenol because the ring carbon attached to the "OH" group is now "C1" The "OH" carbon can be on any carbon atom of the ring, and the compound is still phenol,
- 6-10. What are the name of the following compounds? a. Ca (OH)2 b. Fe . . .
Generally, OH adds "hydroxide" to an inorganic compound's name Moreover, element names aren't capitalized unless at the beginning of a sentence We write iron (II) hydroxide instead of just iron hydroxide as iron takes the form of its +2 oxidation state, out of its 10 oxidation states
- Can you give the IUPAC name for the following (CH_3)_3C-OH . . . - Socratic
So this is a propanol derivative: "2-methylpropan-2-ol" For "isopropyl alcohol", H_3C-CH (OH)CH_3, the longest chain is again three carbons long, and C2 is substituted by -OH, so "propan-2-ol" I think this is right, and I haven't broken any arcane rule Both names seem to be unambiguous
- Question #2c594 - Socratic
The molar concentration of the ammonia is 0 015 mol L > Your textbook is misleading you The 57 6 % figure is calculated as if the ammonia were in the form of "NH"_4"OH" Also, the correct value is 56 7 % (did you mistype?) Step 1 Calculate the formal concentration of the concentrated ammonia Assume that you have 1 L of the concentrated solution "Moles of NH"_3 = 1000 color (red) (cancel
- Question #97503 - Socratic
Here's what I get The general equation for the dissociation of a carboxylic acid is "R-COOH + H"_2"O" ⇌ "R-COO"^"-" + "H"_3"O"^+ All we have to do is write the
- Question #bcb2d - Socratic
calculate moles of Acid, calculate moles of Base subtract, #OH^-# should be in excess, calculate Molarity of #OH^-# , pOH = -log (#OH^-#), then 14-pOH = pH
- Calculating the concentration of excess HCL in E - Socratic
The acid in excess is then titrated with N aOH (aq) of KNOWN concentration we can thus get back to the concentration or molar quantity of M (OH)2 as it stands the question (and answer) are hypothetical
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