- Is it necessary to have oh group of phenol valways at ortho . . . - Socratic
No, the "OH" group in phenol is by definition at "C1" > The structure of phenol is You can draw the structure like this: phenol2 However, the structure is not meta-phenol It is phenol because the ring carbon attached to the "OH" group is now "C1" The "OH" carbon can be on any carbon atom of the ring, and the compound is still phenol,
- On the hydrolysis of esters according to the reaction: HCOO . . . - Socratic
HCOO^(-)(aq) + H_2O(l) rightleftharpoons HCOOH(aq) + OH^(-)(aq) If the solution is diluted, the reaction will shift left, because (i) water isn't in the equilibrium expression, and (ii) each product is in aqueous solution If NaOH is added, then we have increased the concentration of hydroxide ions The reaction will shift left to re-equilibrate and consume the excess OH^- Pressure will have
- Can you give the IUPAC name for the following (CH_3)_3C-OH . . . - Socratic
So this is a propanol derivative: "2-methylpropan-2-ol" For "isopropyl alcohol", H_3C-CH (OH)CH_3, the longest chain is again three carbons long, and C2 is substituted by -OH, so "propan-2-ol" I think this is right, and I haven't broken any arcane rule Both names seem to be unambiguous
- 6-10. What are the name of the following compounds? a. Ca (OH)2 b. Fe . . .
Generally, OH adds "hydroxide" to an inorganic compound's name Moreover, element names aren't capitalized unless at the beginning of a sentence We write iron (II) hydroxide instead of just iron hydroxide as iron takes the form of its +2 oxidation state, out of its 10 oxidation states
- Question #bcb2d - Socratic
calculate moles of Acid, calculate moles of Base subtract, #OH^-# should be in excess, calculate Molarity of #OH^-# , pOH = -log (#OH^-#), then 14-pOH = pH
- Question #74006 - Socratic
(d) is the correct option CH_3CH(OH)CH_2CH_2CH_3 (pentan-2-ol) being secondary alcohol on oxidation first tansformed into ketone CH_3CH(OH)CH_2CH_2CH_3stackrel([O])-> CH_3COCH_2CH_2CH_3 Further oxidation of ketone is difficult but can be performed in extreme conditions and oxidation product is obtained following Popoff's rule Popoff's rule states that during oxidation of unsymmetrical
- Calculating the concentration of excess HCL in E - Socratic
The acid in excess is then titrated with N aOH (aq) of KNOWN concentration we can thus get back to the concentration or molar quantity of M (OH)2 as it stands the question (and answer) are hypothetical
- Question #2c594 - Socratic
The molar concentration of the ammonia is 0 015 mol L > Your textbook is misleading you The 57 6 % figure is calculated as if the ammonia were in the form of "NH"_4"OH" Also, the correct value is 56 7 % (did you mistype?) Step 1 Calculate the formal concentration of the concentrated ammonia Assume that you have 1 L of the concentrated solution "Moles of NH"_3 = 1000 color (red) (cancel
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