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  • Is it necessary to have oh group of phenol valways at ortho . . . - Socratic
    No, the "OH" group in phenol is by definition at "C1" > The structure of phenol is You can draw the structure like this: phenol2 However, the structure is not meta-phenol It is phenol because the ring carbon attached to the "OH" group is now "C1" The "OH" carbon can be on any carbon atom of the ring, and the compound is still phenol,
  • Can you give the IUPAC name for the following (CH_3)_3C-OH . . . - Socratic
    So this is a propanol derivative: "2-methylpropan-2-ol" For "isopropyl alcohol", H_3C-CH (OH)CH_3, the longest chain is again three carbons long, and C2 is substituted by -OH, so "propan-2-ol" I think this is right, and I haven't broken any arcane rule Both names seem to be unambiguous
  • Question #477c5 - Socratic
    On the product side the Carbonic Acid (#H_2CO_3#) is the Conjugate Acid as it is the hydrogen donor to the Conjugate Base (#OH^-#) as it receives the hydrogen ion
  • Question #bcb2d - Socratic
    calculate moles of Acid, calculate moles of Base subtract, #OH^-# should be in excess, calculate Molarity of #OH^-# , pOH = -log (#OH^-#), then 14-pOH = pH
  • Question #1a680 - Socratic
    Now, notice that the oxidation state of nitrogen goes from #color (blue) (+5)# on the reactants' side to #color (blue) (-3)# on the products' side, which basically means that every atom of nitrogen gains #8# electrons
  • Question #0a25a - Socratic
    Lithium hydroxide has a mass of 24 g per mole, so 2 50 g is 0 104 mole Dissolve this in 1 50 L, and the concentration is [LiOH] = 0 104 mol -: 1 50 L = 0 0694 "mol" L Since LiOH is a strong base, it ionizes completely LiOH rarr Li^+ + OH^- Since each one mole of LiOH produces one mole of OH^-, the concentration of OH^- will be 0 0694 mol L as well
  • Question #c76b8 - Socratic
    Answer below Calcium oxide will dissolve to produce Calcium Hydroxide It is as follows: CaO + H_2O to Ca (OH)_2 In essence: "base + water" to "alkali"
  • Question #71ce2 - Socratic
    H^+ + OH^--> H_2O when the acid was added to the resulting solution The H^+ and OH^- react in a 1:1 ratio This tells us that the number of moles of H^+ used will be equal to the number of OH^- moles in solution Likewise, 2 moles of lithium produces 2 moles of OH^- This is also a 1:1 ratio
















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